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Questions taken from the Advanced Placement Calculus test, as indicated.Distance \( x\) (mm) |
0 |
60 |
120 |
180 |
240 |
300 |
360 |
Diameter \(B(x)\) (mm) |
24 |
30 |
28 |
30 |
26 |
24 |
26 |
Solution
Since \(B\) is twice-differentiable on \([0, 360], B\) and \(B'\) are continuous on that interval, so Rolle's theorem holds for both \(B\) and \(B'\). Since \(B(60) = B(180)\), by a corollary to Rolle's Thm, there must exist a \(c_1\) on \((60, 180) \) where \( B'(c_1) = 0.\) Similarly, since \(B(240) = B(360)\), by a corollary to Rolle's Thm, there must exist a \(c_2\) on \((240, 360) \) where \( B'(c_2) = 0.\) Then, applying Rolle's Thm to \(B',\) there must exist a \(c\) on \((c_1, c_2) \) where \( B''(c) = 0.\)