BC Calculus Assignment 35: Exponentials Worksheet A
Class: 5H: BC Calculus
Author: Peter Atlas
Text: Calculus Finney, Demana, Waits, Kennedy
I. Express the logarithms in terms of \( \ln{ 2} \) and \( \ln {3} \) using the rules of arithmetic for logarithms. For example, \( \ln {1.5} = \ln { \left( \frac{3}{2} \right) } = \ln {3} - \ln {2}\).
\( \ln { \left( \frac{4}{9} \right) } \)
Solution
\( 2\ln{2} - 2\ln{3}\)
\(\ln{12} \)
Solution
\( 2\ln{2} + \ln{3} \)
\(\ln{\sqrt[3]{9}} \)
Solution
\( \frac{2}{3}\ln{3} \)
\(\ln{(3 \sqrt{2})} \)
Solution
\( \ln{3} + \frac{1}{2}\ln{2} \)
II. Find \( \frac{dy}{dx}\)
\( \ln \left( x^2 \right) \)
Solution
\( \frac{2}{x} \)
\( \ln { \left( \frac{1}{x} \right) } \)
Solution
\( -\frac{1}{x} \)
\( y = \ln {(2 - \cos{x})} \)
Solution
\( \frac{\sin{x}}{2 - \cos{x}} \)
\( y =\ln {\left( \ln {x} \right)} \)
Solution
\( \frac{1}{x \ln {x}} \)
\( y = x \ln{x} - x \)
Solution
\( \ln{x} \)
\( y = \frac{x \sin{x}}{\sqrt{\sec{x}}} \)
Solution
\( \ln{y} = \ln{x} + \ln{ ( \sin {x} ) } - \frac{1}{2} \ln{\sec {x}}, so \frac{y'}{y} = \frac{1}{x} + \frac{\cos{x}}{\sin{x}} - \frac{1}{2} \frac{\sec {x}\tan {x} } { \sec{x}} \). \(y' = y \left( \frac{1}{x} + \cot {x} - \frac{1}{2} \tan {x} \right) \), and substitute back for \(y\).
\( y = \sqrt{\frac{x}{(x + 1)(x - 3)}} \)
Solution
\( \ln{y} = \frac{1}{2} \left( \ln{x} - \ln{(x + 1)} - \ln{(x - 3)} \right)\), so \(\frac{y'}{y} = \frac{1}{2} \left( \frac{1}{x} - \frac{1}{x + 1} - \frac{1}{x - 3} \right) \). Then \(y' = \frac{1}{2} y \left( \frac{1}{x} - \frac{1}{x + 1} - \frac{1}{x - 3} \right) \) and substitute back for \( y\).
III. Evaluate the following integrals analytically. Support with your calculator.