The equation of the tangent to the curve \(y = e^x\ln{x}\), where \(x = 1\) is
\( y = ex \)
\( \displaystyle y = e^x + 1\)
\( y = e(x - 1)\)
\( y = ex + 1\)
\( y = x - 1 \)
Solution
C
If differentials are used for computation then the cube root of 63 is approximately equal, to the nearest hundredth, to
4.00
3.98
3.93
3.80
3.88
Solution
B
The hypotenuse AB of a right triangle ABC is 5 ft, and one leg, AC, is decreasing at a rate of 2 ft/sec. The rate, in square feet per second, at which the area is changing when AC = 3 is
\( \displaystyle \frac{25}{4} \)
\( \displaystyle \frac{7}{4} \)
\( \displaystyle -\frac{3}{2} \)
\( \displaystyle -\frac{7}{4} \)
\( \displaystyle -\frac{7}{2} \)
Solution
D
The derivative of a function \(f\) is given for all \(x\) by \(f'(x) = x^2(x + 1)^3(x - 4)^2\). The set of \(x\) for which \(f\) has a relative maximum is
{0, -1, 4}
{-1}
{0, 4}
{1}
none of these
Solution
E
If the displacement from the origin of a particle on a line is given by \(s = 3 + (t - 2)^4\), then the number of times the particle reverses direction is
0
1
2
3
none of these
Solution
B
The maximum value of the function \( f(x) = xe^{-x}\) is
\( \displaystyle \frac{1}{e}\)
\( e\)
1
-1
none of these
Solution
A
A rectangle of perimeter 18 in. is rotated about one of its sides to generate a right circular cylinder. The rectangle which generates the cylinder of largest volume has an area, in square inches, of
14
20
\( \displaystyle \frac{81}{4}\)
18
\( \displaystyle \frac{77}{4}\)
Solution
D
If \(f'(x)\) exists on the closed interval \([a, b]\), then it follows that
\(f(x)\) is constant on \([a, b]\)
\( \displaystyle \exists c \in (a, b) \mid f'(c) = 0\)
the function has a maximum value on the open interval \((a, b)\)
the function has a minimum value on the open interval \((a, b)\)
The first-quadrant area bounded below by the x-axis and laterally by the curves \(y = x^2\) and \(y = 4 - x^2\) equals
\( 6 - 2 \sqrt{3}\)
\( \displaystyle \frac{10}{3}\)
\( \displaystyle \frac{8}{3}(2 - \sqrt{2}) \)
\( \displaystyle \frac{4\sqrt{2}}{3}\)
none of these
Solution
C
Find the area bounded by \( \displaystyle y = \frac{4}{1 + x^2}, y = 4, x = 1\), and \(x = -1\).
\( \displaystyle 4 - \frac{4}{\pi}\)
\( 8 - 2 \pi \)
\( 8 - \pi \)
\( \displaystyle 8 - \frac{\pi}{2}\)
\( 2 \pi - 4\)
Solution
B
If \(f(x)\) and \(g(x)\) are both continuous functions on the closed interval \([a, b]\), if \(f(a) = g(a)\) and \(f(b) = g(b)\), and if, further, \(f(x) > g(x) \forall x \in (a, b)\), then it follows that
A particle moves along a line with velocity, in feet per second, \(v = t ^2 - t\). The total distance, in feet, traveled from \(t = 0\) to \(t = 2\) equals
\( \displaystyle \frac{1}{3}\)
\( \displaystyle \frac{2}{3}\)
2
1
\( \displaystyle \frac{4}{3}\)
Solution
D
If \(f'(x) = h(x)\) and \(g(x) = x^3\), then \( \displaystyle \frac{d}{dx} f(g(x)) = \)
\( h(x^3)\)
\( 3x^2h(x)\)
\( h'(x)\)
\( 3x^2h(x^3)\)
\( x^3h(x^3)\)
Solution
D
If \( \displaystyle \frac{dy}{dx} = y \tan {x}\) and \(y = 3\) when \(x = 0\), then, when \( \displaystyle x = \frac{\pi }{3}, y = \)